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115年 - 115 警察特種考試_三等_犯罪防治人員預防組：諮商輔導與婦幼保護#140743(4題)

115年 - 115 警察特種考試_三等_公共安全人員：國家安全情報法制#140742(5題)

115年 - 115 警察特種考試_三等_公共安全人員：情報學#140741(4題)

115年 - 115 警察特種考試_三等_公共安全人員：國土安全與非傳統安全#140740(4題)

115年 - 115 警察特種考試_三等_刑事警察人員：偵查法學#140739(6題)

115年 - 115 警察特種考試_三等_刑事警察人員：犯罪偵查學#140738(29題)

115年 - 115 警察特種考試_三等_外事警察人員（選試英語）：國際警察合作與跨國（境）犯罪防制#140737(4題)

115年 - 115 警察特種考試_三等_外事警察人員（選試英語）：外事警察學#140736(4題)

115年 - 115 警察特種考試_三等_行政警察人員：偵查法學與犯罪偵查#140735(27題)

115年 - 115 警察特種考試_三等_行政警察人員：警察學與警察勤務#140734(27題)

25. Which of the following statement is correct related to general and gene-specific transcription factors in eukaryotes? (A) TATA-box-binding protein (TBP) binds to the minor groove of DNA, bends the consensus TATA DNA, and is required for most members of class I, II and III genes. (B) For RNAP III, TBP is a component of the general transcription factor TFIIIC. (C) The bZIP transcription factors dimerize through a basic domain and bind to target DNA through a leucine zipper. (D) TFIIE and TFIIH are essential for promoter clearance and transcription elongation. (E) The Cys2His2-zinc finger of TFIIIA is composed of an antiparallel beta-sheet followed by an alpha-helix, and the beta-sheet recognizes and binds to specific DNA sequences in the major groove.

24. Which of the following statement is correct in eukaryotic transcription? (A) Yeast Gcn4 controls amino acid metabolism, containing a domain using the basic region to bind to DNA and helix-loop-helix to form a protein dimer. (B) The carboxyl-terminal domain of RNA polymerase is phosphorylated prior to the formation of the initiation complex. (C) By adding of excess acetyltransferase to in vitro transcription assay, it is likely lead to a tighter association of histone with DNA, resulting in reduced transcription. (D) TAF1 of the general transcription factor TFIID is a helicase and a histone acetyltransferase. (E) The high mobility group protein (HMG I(Y)) plays a role in interferon-ẞ (IFN-ẞ) transcription by bending the DNA, causing more activators to bind and interact with each other to enhance transcription.

23. Which of the following is true for eukaryotic Class I and III general transcription factors, except: (A) TFIIIB and TFIIIC are required for all "classical" class III genes. (B) TFIIIC is an assembly factor that helps TFIIIB to bind to a region just upstream of the transcription start site. (C) Human SL1 is an assembly factor that helps the UPE-binding factor of RNA polymerase I to bind to the core promoter element. (D) TFIIIA is a zinc finger protein & is required for transcription of the 5S rRNA genes, but not the tRNA genes. (E) For the class I transcription, human SL1 consists of TATA-binding protein (TBP) and TBP-associated factors (TAFs), which are different from TAFs found in TFIID.

10. Why is a frameshift mutation located at the beginning of a coding region generally more detrimental to protein function than a missense mutation? Briefly explain the reason. (4 pts)

9. You observe that adding DNase to a bacterial culture prevents the bacteria from acquiring a new hereditary trait. Based on this observation, which gene transfer mechanism is occurring (Transformation, Transduction, or Conjugation)? Explain your reasoning. (4 pts)

8. In quantitative PCR (qPCR), why do we focus on the Ct value (Threshold Cycle) rather than the final amount of product at the end of the reaction? (3 pts) Briefly define what the Ct value represents. (3 pts)

徐喬-經濟學(資料太多優化中)

講師：【站僕】摩檸Morning.

王立杰-幼稚教育考試精粹

講師：【站僕】摩檸Morning.

陳萱-公民

講師：【站僕】摩檸Morning.

公債發行之目的

課程：徐喬-經濟學(資料太多優化中)
章節：Ch22.古典學派

教哲-新馬克思=批判理論=法蘭克福學派

課程：徐喬-經濟學(資料太多優化中)
章節：Ch22.古典學派

行政學人物重點

課程：徐喬-經濟學(資料太多優化中)
章節：Ch22.古典學派

48.依據「職業安全衛生管理辦法」之規定，雇主對電氣機車、蓄電池機車、內燃機車、蒸氣汽車等， 應多久就整體定期實施檢查一次？ (A)每半年(B)每一年(C)每兩年(D)每三年

5 國際法院在 2010 年公布有關科索沃獨立宣言合法性的諮詢意見。關於這份諮詢意見，下列敘述 何者正確？ (A)此諮詢意見係由塞爾維亞向國際法院提出請求而作成 (B)國際法院認為科索沃宣布獨立之行為未違反國際法 (C)國際法院認為人民自決權於殖民地人民範疇外亦適用 (D)國際法院認為其他國家承認科索沃為獨立國家有溯及至宣布獨立之日的效力

21.如果就心理測驗(psychological testing)和心理衡鑑(psychological assessment)加以比較，下列的敘述中，那一項的敘述是不適切的？ (A)心理測驗是一種工具，而心理衡鑑是解決問題的過程 (B)心理測驗是測量個案的特定心理向度，而心理衡鑑是針對個案的臨床問題做整體的評估 (C)心理測驗的結果較適用於特定個案問題的深入了解，而心理衡鑑的結果較適合於做個別差異比較，反映個案在團體中的相對位置 (D)實施心理測驗可以測量到智力、性向、成就等能力特質，而心理衡鑑關心的不是分數的多寡，而是個案問 題是如何形成的？如何協助個案解決問題？

29 承上題，該都會區每日發生交通事故 4 次（含）以上的機率為何？Pr (X=x)= ，x=0, 1, 2,…, ∞，λ>0 ! (A) 0.353 (B) 0.168 (C) 0.647 (D) 0.832

8.下列何者是 T 細胞的正向免疫檢查點(positive immune checkpoint)，屬於活化型受體？ (A)CTLA-4 (B)CD28 (C)PD-1 (D)LAG-3