22. Calculate the standard enthalpy change for the reaction 2C8H18(l) + 17O2(g) → 16CO(g) + 18H2O(l). Given: 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l)  △H° = –11,020 kJ/mol 2CO(g) + O2(g) → 2CO2(g)   △H° = –566.0 kJ/mol (A) 10,450 kJ/mol (B) 6,492 kJ/mol (C) 15,550 kJ/mol (D) –6,492 kJ/mol