題組內容

1. Solution

(b)

\[ \begin{bmatrix} 1 & 3 & 1 & -2 \\ 2 & 5 & 1 & -5 \\ 1 & 2 & 3 & 6 \end{bmatrix} \approx \begin{bmatrix} 1 & 3 & 1 & -2 \\ 0 & -1 & -1 & -1 \\ 0 & -1 & 2 & 8 \end{bmatrix} \approx \begin{bmatrix} 1 & 3 & 1 & -2 \\ 0 & 1 & 1 & 1 \\ 0 & -1 & 2 & 8 \end{bmatrix} \approx \begin{bmatrix} 1 & 3 & 1 & -2 \\ 0 & 1 & 1 & 1 \\ 0 & 0 & 3 & 9 \end{bmatrix} \]

\[ \begin{bmatrix} 1 & 0 & -2 & -5 \\ 0 & 1 & 1 & 1 \\ 0 & 0 & 3 & 9 \end{bmatrix} \approx \begin{bmatrix} 1 & 0 & -2 & -5 \\ 0 & 1 & 1 & 1 \\ 0 & 0 & 1 & 3 \end{bmatrix} \approx \begin{bmatrix} 1 & 0 & 0 & 1 \\ 0 & 1 & 0 & -2 \\ 0 & 0 & 1 & 3 \end{bmatrix} \]

阿摩線上測驗 · 2026-09-04T10:32:07+08:00

(b) bmatrix 1 & 3 & 1 & -2 \ 2 & 5 & 1 & -5 \ 1 & 2 & 3 & 6 bmatrix ≈ bmatrix 1 & 3 & 1 & -2 \ 0 & -1 & -1 & -1 \ 0 & -1 & 2 & 8 bmatrix ≈ bmatrix 1 & 3 & 1 & -2 \ 0 & 1 & 1 & 1 \ 0 & -1 & 2 & 8 bmatrix ≈ bmatrix 1 & 3 & 1 & -2 \ 0 & 1 & 1 & 1 \ 0 & 0 & 3 & 9 bmatrix bmatrix 1 & 0 & -2 & -5 \ 0 & 1 & 1 & 1 \ 0 & 0 & 3 & 9 bmatrix ≈ bmatrix 1 & 0 & -2 & -5 \ 0 & 1 & 1 & 1 \ 0 & 0 & 1 & 3 bmatrix ≈ bmatrix 1 & 0 & 0 & 1 \ 0 & 1 & 0 & -2 \ 0 & 0 & 1 & 3 bmatrix

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