1.1 (10%) Let the random variable X have the pmf f(x) = ((|x| + 1)^2)/9, x = -1, 0, 1 (a) (5%) Find E(X).

1.5 (10%) Let X and Y denote the tarsus lengths of male and female grackles, and $$\mu_X$$ and $$\mu_Y$$ are the male and female mean tarsus lengths, respectively. Two samples of size 25 are taken from each populations assumed to be normally with equal variances. The male sample has a mean of 35.5 and standard deviation 3.0 while the female sample has a mean of 33.0 and standard deviation 4.0. We want to test the hypothesis that the mean tarsus lengths are equal against the hypothesis that male has longer tarsus lengths. (a) $(2\%)$ Write the null and alternative hypotheses with symbols.

1.1 (10%) Let the random variable X have the pmf $$f(x) = \frac{(|x| + 1)^2}{9}$$, $$x = -1, 0, 1$$

(a) \((5\%)\) Find \(E(X)\).

相關申論題

相關試卷

1.1 (10%) Let the random variable X have the pmf $$f(x) = \frac{(|x| + 1)^2}{9}$$, $$x = -1, 0, 1$$ (a) \((5\%)\) Find \(E(X)\).

相關申論題

相關試卷

1.1 (10%) Let the random variable X have the pmf $$f(x) = \frac{(|x| + 1)^2}{9}$$, $$x = -1, 0, 1$$

(a) \((5\%)\) Find \(E(X)\).