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最新試卷
115年 - 115 普通考試_食品衛生檢驗:食品檢驗分析與化學概要#142180(4題)
115年 - 115 普通考試_圖書資訊管理:圖書資訊學概要#142179(27題)
115年 - 115 普通考試_水土保持工程:集水區經營與水文學概要#142178(4題)
115年 - 115 普通考試_檔案管理:檔案技術及應用服務概要#142177(5題)
115年 - 115 普通考試_測量製圖:空間資訊概要#142176(4題)
115年 - 115 普通考試_環保行政、環保技術:環境污染防治技術概要#142175(6題)
115年 - 115 普通考試_輪機技術:船用電學與自動控制概要#142174(4題)
115年 - 115 普通考試_農業技術:植物保護概要#142173(5題)
115年 - 115 普通考試_環境工程:廢棄物處理工程概要#142172(4題)
115年 - 115 普通考試_航空器維修:航空發動機概要#142171(11題)
最新試題
25. Which of the following statement is correct related to general and gene-specific transcription factors in eukaryotes? (A) TATA-box-binding protein (TBP) binds to the minor groove of DNA, bends the consensus TATA DNA, and is required for most members of class I, II and III genes. (B) For RNAP III, TBP is a component of the general transcription factor TFIIIC. (C) The bZIP transcription factors dimerize through a basic domain and bind to target DNA through a leucine zipper. (D) TFIIE and TFIIH are essential for promoter clearance and transcription elongation. (E) The Cys2His2-zinc finger of TFIIIA is composed of an antiparallel beta-sheet followed by an alpha-helix, and the beta-sheet recognizes and binds to specific DNA sequences in the major groove.
24. Which of the following statement is correct in eukaryotic transcription? (A) Yeast Gcn4 controls amino acid metabolism, containing a domain using the basic region to bind to DNA and helix-loop-helix to form a protein dimer. (B) The carboxyl-terminal domain of RNA polymerase is phosphorylated prior to the formation of the initiation complex. (C) By adding of excess acetyltransferase to in vitro transcription assay, it is likely lead to a tighter association of histone with DNA, resulting in reduced transcription. (D) TAF1 of the general transcription factor TFIID is a helicase and a histone acetyltransferase. (E) The high mobility group protein (HMG I(Y)) plays a role in interferon-ẞ (IFN-ẞ) transcription by bending the DNA, causing more activators to bind and interact with each other to enhance transcription.
23. Which of the following is true for eukaryotic Class I and III general transcription factors, except: (A) TFIIIB and TFIIIC are required for all "classical" class III genes. (B) TFIIIC is an assembly factor that helps TFIIIB to bind to a region just upstream of the transcription start site. (C) Human SL1 is an assembly factor that helps the UPE-binding factor of RNA polymerase I to bind to the core promoter element. (D) TFIIIA is a zinc finger protein & is required for transcription of the 5S rRNA genes, but not the tRNA genes. (E) For the class I transcription, human SL1 consists of TATA-binding protein (TBP) and TBP-associated factors (TAFs), which are different from TAFs found in TFIID.
最新申論題
10. Why is a frameshift mutation located at the beginning of a coding region generally more detrimental to protein function than a missense mutation? Briefly explain the reason. (4 pts)
9. You observe that adding DNase to a bacterial culture prevents the bacteria from acquiring a new hereditary trait. Based on this observation, which gene transfer mechanism is occurring (Transformation, Transduction, or Conjugation)? Explain your reasoning. (4 pts)
8. In quantitative PCR (qPCR), why do we focus on the Ct value (Threshold Cycle) rather than the final amount of product at the end of the reaction? (3 pts) Briefly define what the Ct value represents. (3 pts)
最新課程
【警鴿】憲法考前30天衝刺(日期、數字、口訣)
講師:
小摩喵(課程:警鴿系列)
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【這是精華中的精華了】 再怎樣,把這些死背題目考前拿出來翻一下!! 希望對你們有幫助!!! ●筆者在...
閱讀測驗作答技巧【適用多益、全民英檢等測驗】
講師:
小笨蛋
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https://docs.google.com/forms/d/e/1FAIpQLSfjRRPyZhBRhxX5vY7a7x9DqE7GZfvheFPwEyeT3qlfD7dIpg/viewform...
全民英檢初級課程
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台中大雅家教-睿智數學及英文家教,王瑞志老師
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提供全民英檢初級課程,助你拿到證書。
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行政與行政法
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行政法
最新討論
48.依據「職業安全衛生管理辦法」之規定,雇主對電氣機車、蓄電池機車、內燃機車、蒸氣汽車等, 應多久就整體定期實施檢查一次? (A)每半年(B)每一年(C)每兩年(D)每三年
5 國際法院在 2010 年公布有關科索沃獨立宣言合法性的諮詢意見。關於這份諮詢意見,下列敘述 何者正確? (A)此諮詢意見係由塞爾維亞向國際法院提出請求而作成 (B)國際法院認為科索沃宣布獨立之行為未違反國際法 (C)國際法院認為人民自決權於殖民地人民範疇外亦適用 (D)國際法院認為其他國家承認科索沃為獨立國家有溯及至宣布獨立之日的效力
21.如果就心理測驗(psychological testing)和心理衡鑑(psychological assessment)加以比較,下列的敘述中,那一項的敘述是不適切的? (A)心理測驗是一種工具,而心理衡鑑是解決問題的過程 (B)心理測驗是測量個案的特定心理向度,而心理衡鑑是針對個案的臨床問題做整體的評估 (C)心理測驗的結果較適用於特定個案問題的深入了解,而心理衡鑑的結果較適合於做個別差異比較,反映個案在團體中的相對位置 (D)實施心理測驗可以測量到智力、性向、成就等能力特質,而心理衡鑑關心的不是分數的多寡,而是個案問 題是如何形成的?如何協助個案解決問題?
29 承上題,該都會區每日發生交通事故 4 次(含)以上的機率為何?Pr (X=x)= ,x=0, 1, 2,…, ∞,λ>0 ! (A) 0.353 (B) 0.168 (C) 0.647 (D) 0.832
8.下列何者是 T 細胞的正向免疫檢查點(positive immune checkpoint),屬於活化型受體? (A)CTLA-4 (B)CD28 (C)PD-1 (D)LAG-3