2.設二次實係數多項式\( y = -x^2 + a(x - 1)^2 \),其函數圖形頂點的x坐標為−1,試問a的值為何?
(A)\(-\frac{1}{2}\)
(B)\(-\frac{1}{4}\)
(C)1/4
(D)1/2
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統計: A(0), B(0), C(0), D(1), E(0) #3883941
統計: A(0), B(0), C(0), D(1), E(0) #3883941