20. Consider a purely resistive heater connected to an AC power source (rms
voltage 120 V, frequency 60 Hz) with an average heating power of 1 kW. If an
inductor is connected in series with the heater, causing the average heating
power to drop to 1/4 of its original value, what is the phase angle between the
voltage and the current?
(A) 15°
(B) 30°
(C) 45°
(D) 60°
(E) 90°
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詳解 (共 2 筆)
#7394891
所以這題是考實功率和阻抗的關係
看功率推電流,功率剩1/4,電流剩1/2因為P=I平方乘以R
再來看電流推阻抗Z=IR
所以電流變1/2倍,阻抗Z是電阻R的2倍
然後代入相位角公式cosfin=R/Z=1/2
所以fin=60度
ㅤㅤ
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