題組內容

2. A hydrogen atom in a state having a binding energy (the energy required to remove an electron) of 0.85 eV makes a transition to a state with an excitation energy (the difference between the energy of the state and that of the ground state) of 10.2 eV.

(b) What are the higher quantum number and lower quantum number of the transition producing this emission? 

詳解 (共 1 筆)

助人為本
助人為本
詳解 #7384764
2026/05/26
所以解這題只要背一個公式即可:氫原子能階公式
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所以上一題我們已經知道結合能為0.85eV
所以初始能量為-0.85eV
代入公式求解，可以得到n=4
再來是求激發能所對應的能量為-13.6+10.2=-3.4eV
同樣代入公式可以得到n=2