12. An alpha particle (q = +2e, m =
) travels in a circular path of radius 4.50 cm in a uniform magnetic field with B = 1.20 T. Through what potential difference (volts) was it accelerated (from rest) to have the kinetic energy required for this path?
詳解 (共 1 筆)
助人為本
詳解 #7384061
所以解這題磁場偏轉可以背一個公式下去做
就是r=m*v/q*B
把值代入可以求出v是多少
然後題目要反求電壓v是多少
上一題算出來的速度v代入這個公式
再來只要利用qV=1/2mv^2來解就好
最後算出
